Lowest Energy of Particle in 1-D Box: 2 eV

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Homework Help Overview

The problem involves a particle confined in a one-dimensional box with impenetrable walls, given an energy eigenvalue of 2 eV. Participants are exploring the concept of energy levels in quantum mechanics, specifically how to determine the lowest energy state of the particle based on the provided information.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between the energy eigenvalue and the zero point energy, questioning how to derive the lowest energy state from the given eigenvalue. Some participants suggest that additional information, such as the mass of the particle or the length of the box, is necessary to fully resolve the problem.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning the completeness of the information provided. Some have proposed potential solutions based on the wave function, while others emphasize the need for more data to clarify the situation.

Contextual Notes

There is a noted lack of information regarding the mass of the particle and the dimensions of the box, which are critical for determining the energy levels accurately. Additionally, the quantum number associated with the 2 eV eigenstate remains unspecified, leading to further uncertainty in the discussion.

Amith2006
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Homework Statement


1) A particle inside a one dimensional box with impenetratable walls at x=-a and x=+a has an energy eigenvalue of 2 eV. What is the lowest energy that the particle can have?


Homework Equations


E(n) = (n^2)E(o)
where E(o)=h^2/(8mL^2)


The Attempt at a Solution



I started in the following way:
If E(o) is the zero point energy. Then,
2 eV = (n^2)E(o)
Where does it lead to?
 
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I don't think it leads anywhere else. Are you sure they didn't give you some other kind of information?
 
I forgot to include the wave function of the particle. When u asked whether any other information was given, I struck a way to solve this problem.
I solved it in the following way:
Let w denote the wave function of the particle.
w(n)= [n^2]E(o)
From the wave function of the particle it is clear that n=2
w(2)=2 eV = [2^2]E(o)
i.e. E(o) = 0.5 eV
Is it right?
 

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The problem is still ill-determined pending knowledge of either the mass and length of the box, or the quantum number (n) describing the 2eV eigenstate. Perhaps you are given a picture of the wavefunction for the 2eV eigenstate? If so, you can count zeros to determine the quantum number, otherwise, there isn't enough information to answer the problem.
 
mufusisrad said:
The problem is still ill-determined pending knowledge of either the mass and length of the box, or the quantum number (n) describing the 2eV eigenstate. Perhaps you are given a picture of the wavefunction for the 2eV eigenstate? If so, you can count zeros to determine the quantum number, otherwise, there isn't enough information to answer the problem.

Did u see the diagram? Isn't that enough to solve the problem?
 
Amith2006 said:
I forgot to include the wave function of the particle. When u asked whether any other information was given, I struck a way to solve this problem.
I solved it in the following way:
Let w denote the wave function of the particle.
w(n)= [n^2]E(o)
From the wave function of the particle it is clear that n=2
w(2)=2 eV = [2^2]E(o)
i.e. E(o) = 0.5 eV
Is it right?

That's right.
 
:cool: Thats cool!I think I am getting better. Thanks.
 

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