LR Circuit Analysis: Find Current i When Switch is Opened

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Homework Help Overview

The discussion revolves around analyzing the behavior of an LR circuit when a switch is opened after being closed for a long time. Participants are exploring the implications of inductance on current flow at the moment the switch is opened.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the initial current through the inductor and question whether it will remain the same or die out instantly when the switch is opened. There are inquiries about the reasoning behind the calculated current of 9A and the implications of Lenz's Law on current behavior in inductors.

Discussion Status

Some participants have provided insights into the nature of current in inductors, particularly regarding its persistence when the switch is opened. There is an ongoing exploration of how current behaves in inductors, with multiple interpretations being considered.

Contextual Notes

Participants are grappling with the concept of instantaneous changes in current within inductors, questioning the assumptions about current behavior and the definitions involved in the problem setup.

utkarshakash
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Homework Statement


Switch S is closed for long time in the figure shown. Find the current i as soon as the switch is opened.


The Attempt at a Solution



At t=∞ inductor behaves as closed circuit. So, I can simply replace it with a wire and calculate the current which comes out to be 9A. But I can't understand what will happen when the switch is opened. Will the current die out instantly? Will it be the same as before?
 

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utkarshakash said:

Homework Statement


Switch S is closed for long time in the figure shown. Find the current i as soon as the switch is opened.

The Attempt at a Solution



At t=∞ inductor behaves as closed circuit. So, I can simply replace it with a wire and calculate the current which comes out to be 9A. But I can't understand what will happen when the switch is opened. Will the current die out instantly? Will it be the same as before?
First of all, how did you get 9 A? Is that what you get for the current through the inductor ? (Yes, I assume you're getting this while the switch is still closed.) ... but how did you get that?
 
SammyS said:
First of all, how did you get 9 A? Is that what you get for the current through the inductor ? (Yes, I assume you're getting this while the switch is still closed.) ... but how did you get that?

Sorry. I misunderstood the question. It asks for the current through the inductor. I calculated the current flowing through the battery instead. btw I got the correct answer.
 
So what current flows through the inductor?

The current through the battery ceases immediately when the switch is opened, but the current through the inductor does not. Think of Lenz's Law.
 
utkarshakash said:
1. Will the current die out instantly? Will it be the same as before?


Can current EVER die out instantly in an inductor? Can current change in an inductor if you don't give it any time to change?
 

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