Mesh Current Analysis: Find Current Through Short Circuit Wire

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Discussion Overview

The discussion revolves around the analysis of a circuit involving mesh current analysis to determine the current through a short circuit wire between two points (a and b). The context includes a homework problem with specific resistor values and voltages.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant presents a solution involving mesh current equations and calculates currents ia and ib, concluding that ia=0 and ib=0.05 Amps.
  • Another participant agrees with the calculated values and discusses the implications of varying V2, suggesting that if V2 were significantly higher, it could force current into source V1, akin to charging a battery.
  • A later reply questions how V1 ceases to supply current, leading to an explanation that current stops when V1 is connected to a voltage equal to its own, resulting in no net current flow.

Areas of Agreement / Disagreement

Participants generally agree on the calculated values of currents but explore the conceptual implications of V1's behavior under different voltage conditions. The discussion includes questions and clarifications, indicating some uncertainty about the conditions under which V1 stops supplying current.

Contextual Notes

There are unresolved aspects regarding the assumptions made in the mesh current analysis and the implications of varying voltage levels on the circuit behavior.

Tekneek
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Homework Statement



I need to find the Current through short circuit wire (between a and b).

Homework Equations



All the resistor values are same, 100 Ohms
V1 = 5V
V2 = 10V

The Attempt at a Solution



Loop A
ia*(R2+R4+R1) - ib*(R4) = 5

Loop B
10 + (ib-ia)*R4 + ib*R3 = 0
ib*(R4+R3) - ib*R4 = -10

After plugging in all the values,

300ia - 100ib = 5
-100ia + 200ib = -10

ia= 0, ib= 0.05 Amps

Current through the circuit is same as ib because the current is not going to flow through R5.
But the problem is I don't think it is possible for ia to be 0...
 

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ia= 0, ib= 0.05 Amps
That looks right.

If V2 were much higher, say 60v, it would be forcing current into source V1, similar to charging a battery. So there is some point where V1 ceases to supply current, but before its current goes negative. This point occurs when V2=10v here.

Yes, the current in the s/c is that current in R3.
 
NascentOxygen said:
That looks right.

If V2 were much higher, say 60v, it would be forcing current into source V1, similar to charging a battery. So there is some point where V1 ceases to supply current, but before its current goes negative. This point occurs when V2=10v here.

Yes, the current in the s/c is that current in R3.

Thanks. But how does V1 stop supplying current?
 
Tekneek said:
Thanks. But how does V1 stop supplying current?
When it finds itself connected to a voltage that's exactly equal to its own voltage. Current can flow neither IN nor OUT.
 

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