1. The problem statement, all variables and given/known data See attached image for circuit diagram and givens. The switch has been closed for a very long time. a) What is the charge on the capacitor? b) The switch is opened at t=0 s. What current initially flows? 2. Relevant equations V = IR Q=CV I=I0e-t/(RC) 3. The attempt at a solution Since the switch has been open for a long time, no current flows through the 10 Ohm resistor. Therefore, I = 100V/(60 Ohm + 40 Ohm) = 1 Amp, V = 1Amp*40 Ohm, and Q = 2uF * 40V = 80uC. So my question is: Is the current that initially flows after the switch opens at t=0 s just due to the battery? So it would just be 1Amp? I'm having trouble understanding how to find the current at part b.