LR Circuit: Solving for Charge Flow?

[cupid.callin]

I solved it :p

Homework Statement

The Attempt at a Solution

I need help with part (a)

Current in LR circuit, i = i_o (1 - e^{-t/\tau}) and \tau = \frac{L}{R}

so, \frac{dq}{dt} = i_0 (1 - e^{-t/\tau})

integrating it is not giving me the correct answer.

 

[Liquidxlax]

I solved it :p

Homework Statement

The Attempt at a Solution

I need help with part (a)

Current in LR circuit, i = i_o (1 - e^{-t/\tau}) and \tau = \frac{L}{R}

so, \frac{dq}{dt} = i_0 (1 - e^{-t/\tau})

integrating it is not giving me the correct answer.

just integrate with respect to t, dq/dt = ... dq = ...dt

 

[cupid.callin]

its solved ... i wrote it on the top