The Attempt at a Solution
When the switch is off , the current in the inductor doesn't drop to zero instantaneously . The current in the loop consisting of inductor , resistor and two bulbs will decay gradually . Now since there is a complete circuit involving the two bulbs, a gradually decreasing current will flow and both of them will die out simultaneously with some delay . I think answer should be option b) .
Answer given is option d) with the reason that branch having inductor has some inductance which delays B2 to die out promptly .
What is my mistake ?
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