The discussion focuses on calculating the Mach value of a jet that accelerates from rest at an acceleration of 12 m/s² for 41 seconds at a temperature of 12 degrees Celsius. The correct formula for velocity, derived from the equation \( v = a \times t \), yields a final velocity of 492 m/s. The speed of sound at 12 degrees Celsius is approximately 339.08 m/s, leading to a Mach number calculated using the formula \( \text{Mach} = \frac{v}{v_s} \), resulting in a Mach value of approximately 1.45.
PREREQUISITESAerospace engineers, physics students, and anyone interested in understanding jet propulsion and aerodynamics will benefit from this discussion.
soulja101 said:Homework Statement
If the temperature is 12 degrees and a jet accelerates at rest at 12ms2 for 41s, then what is the Mach value for the jet at the end of 41 seconds
Homework Equations
mach#=vovs
speed of sound equation
The Attempt at a Solution
v=12degrees
a=12ms2
v=339,08ms
m#=vo/vs