The Maclaurin series expansion for ##(1+z)^\alpha## is as follows:(adsbygoogle = window.adsbygoogle || []).push({});

$$(1+z)^\alpha = 1 + \sum_{n=0}^\infty \binom{\alpha}{n}z^n$$ with $$|z|<1$$

What I don't understand is why is ##|z|<1##?

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# Maclaurin series of an elementary function question

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