Magneostatics - hollow sphere of spontaneous magnetization

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SUMMARY

The discussion focuses on the analysis of a hollow magnetic sphere with spontaneous magnetization M, detailing the magnetic field strength in both the internal cavity (rb). It establishes that the internal field strength is zero and that the external field strength behaves like that of a dipole moment, defined as m = 4πM(b³-a³)/3. Additionally, it presents the formula for the square of the external field strength as H² = (3cos²θ + 1)(M(b³-a³)/3r³)², emphasizing the use of superposition to derive these results.

PREREQUISITES
  • Understanding of magnetostatics principles
  • Familiarity with the concept of spontaneous magnetization
  • Knowledge of magnetic field equations, specifically H = b/μ₀ - M
  • Proficiency in vector calculus, particularly curl and cross product operations
NEXT STEPS
  • Study the principle of superposition in magnetostatics
  • Learn about dipole magnetic fields and their mathematical representations
  • Explore the implications of spontaneous magnetization in different materials
  • Review vector calculus applications in electromagnetism
USEFUL FOR

This discussion is beneficial for physics students, particularly those studying electromagnetism, as well as researchers and educators focusing on magnetostatics and magnetic materials.

XCBRA
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Homework Statement



a) A hollow magnetic sphere of internal radius a and external radius b, has a uniform spontaneous magnetization M per unit volume. SHow that the field strength in the internal cavity (r<a) is zero, and that the external field strength (r>b) is the same as that of a dipole moment [itex]m = 4 \pi M (b^3-a^3)/3[/itex] , the total moment of the hollow sphere.

b) Show also that the square of the field strength outside the sphere at a point measured from the centre of the sphere and with the respect to the direction of magnetization, is
[tex]H^2 = (3\cos^2\theta +1)({\frac{M(b^3-a^3)}{3r^3}})^2.[/tex]



Homework Equations


[tex]J_b = curl M[/tex]
[tex]K_b = M x n[/tex]
[tex]H=b/\mu_0 - M [/tex]

The Attempt at a Solution



I am not sure at all how to approach this problem. I am not entirly sure how to use the spontaneous magnetization to model the problem. Any hint of how to look at this problem or any material that would help me learn about the principles involved would b greatly apreciated. Thank yuo for your time.
 
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XCBRA said:

Homework Statement



a) A hollow magnetic sphere of internal radius a and external radius b, has a uniform spontaneous magnetization M per unit volume. SHow that the field strength in the internal cavity (r<a) is zero, and that the external field strength (r>b) is the same as that of a dipole moment [itex]m = 4 \pi M (b^3-a^3)/3[/itex] , the total moment of the hollow sphere.

b) Show also that the square of the field strength outside the sphere at a point measured from the centre of the sphere and with the respect to the direction of magnetization, is
[tex]H^2 = (3\cos^2\theta +1)({\frac{M(b^3-a^3)}{3r^3}})^2.[/tex]


For part a), use principle of superposition. Consider superimposing two sphere of radius b and a of the same magnetization density but in opposite direction.

For part b), shouldn't be too hard once you get part a) since the field of a dipole is well known and can be found in your textbook somewhere.
 

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