Magnesium ion entering a mass spectrometer. find r

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SUMMARY

The discussion focuses on calculating the radius of deflection for a magnesium ion (Mg 2+) in a mass spectrometer. The ion travels at a velocity of 60000 m/s within a magnetic field of 800 T. The initial calculation yielded a radius of 9.45 x 10^-6 m, but the correct answer is 9.39 x 10^-6 m. The error identified involves the need to convert the molar mass of magnesium from grams per mole to kilograms per atom using Avogadro's constant.

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Homework Statement



A magnesium ion (Mg 2+) traveling at 60000 m/s enters a mass spectrometer with a magnetic field intensity of 800T. Calculate the radius of deflection forthe magnesium ion.

800T = |B|
24.31g/mol = m
60000 m/s = v
1.66* 10^-27= Atomic mass unit
r=?

Homework Equations



r= (mv)/ |q||B|

The Attempt at a Solution



(24.31g/mol )(1.66* 10^-27 kg)(60000m/s)
= ------------------------------------------------------
(1.60 * 10^-19 C)(2)(800T)

= 9.45* 10^-6 m

but the right answer is supposed to be 9.39* 10^-6m


can anyone let me know where I've made a mistake?
Thank you in advance!
 
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you made a mistake.
what is (24.31g/mol )(1.66* 10^-27 kg) in the numerator?

what you need to do is - convert g/mol into kg/atom, using the avogadro's constant.

think and try it.
 

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