Mass-to-Charge Ratio of an Ion in Mass Spectrometer

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SUMMARY

The discussion focuses on calculating the mass-to-charge ratio (m/q) of an ion in a mass spectrometer using given electric and magnetic fields. The relevant equations are v = E/B for velocity and m = qrB/V for mass. Participants noted discrepancies in calculated velocity, with one user obtaining 51851 m/s, which was corrected to 5.2 x 10^4 m/s. Ultimately, the exercise emphasizes that the mass-to-charge ratio, rather than mass alone, is the required output.

PREREQUISITES
  • Understanding of mass spectrometry principles
  • Familiarity with electric and magnetic fields
  • Knowledge of basic physics equations related to motion
  • Ability to perform unit conversions and calculations
NEXT STEPS
  • Research the concept of mass-to-charge ratio in mass spectrometry
  • Study the effects of electric and magnetic fields on charged particles
  • Learn about the velocity selector in mass spectrometers
  • Explore the significance of precision in scientific calculations
USEFUL FOR

This discussion is beneficial for physics students, educators, and professionals working with mass spectrometry, particularly those focusing on ion analysis and charge measurements.

camel-man
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Homework Statement


Consider fields of 1.4e5 N/C and 2.7 T within a velocity selector. If the charge then exits and encounters a field of 1.4 T and radius of 2.4 mm within the mass spectrometer, what would be the mass to charge ratio of this ion?

Homework Equations


v = E/B
m = qrB/V[/B]

q = 1.6 x 10 ^-19C
r = 2.4 x 10^-3 m
B = 1.4 T

The Attempt at a Solution



I got 51851 m/s for v

and my answer came out way off when I plugged it in for m.

I have the answer but when I try to do it myself. I get the wrong answer.
 
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The exercise asks for m/q, not for m. What did you get ?
And what exactly do you mean when you say 'I get the wrong answer' ?

By the way: you got 5.2 x 104 m/s, not 51851 m/s : you can't achieve five digit accuracy when all you're given is two digit numbers! But v wasn't wanted.
(However, when you work out this exercise with the given numbers in the expression for m/q, you do end up to within 1 promille of m/q of a known particle...what a coincidence!)
 

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