Magnetic field and charged particle help

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A charged particle moving at a 13° angle to a magnetic field experiences a magnetic force F. To find the angle at which the same particle will experience a force of 2.4F while maintaining the same speed, the relationship between the force, speed, charge, and angle must be considered. The magnetic force is influenced by the strength of the magnetic field and the angle between the particle's velocity and the field direction. The problem requires applying Ampere's law, which relates the magnetic field to the current and geometry of the system. Understanding the equation that describes the force on a charged particle in a magnetic field is essential for solving this problem.
MrDMD83
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When a charged particle moves at an angle of 13° with respect to a magnetic field, it experiences a magnetic force of magnitude F. At what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 2.4F?
 
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Please post your attempt at solving this problem.
 
It says to use Ampere's law

Sum of(Bparallel x change in length) = Permeability of free space x Amperage. This is due by noon today. Please help.
 
It says to use Ampere's law

Sum of(Bparallel x change in length) = Permeability of free space x Amperage. This is due by noon today. Please help.
 
MrDMD83 said:
Sum of(Bparallel x change in length) = Permeability of free space x Amperage. This is due by noon today. Please help.
You have a charged particle moving in a magnetic field. The force depends on the strength of the field, the velocity of the charge, the magnitude and sign of the charge, and the angle between the velocity direction and the field direction. In this problem all you are changing is the angle between the directions. Do you know the equation that espresses this relationship?
 

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