# Magnetic field and current tendency

ayalala
1. Two-wire, long, straight parallel 10cm distant from each other, as shown in the chart.
Upper wire current issue I1 = 6A trend into the top level.
A. What are the strength of the current tendency I2 bottom wire, if the magnetic field equivalent at P equal Zero?
b. What is the equivalent magnetic field point? Q
C. What is the equivalent magnetic field point S?

2. not sure what to use

3. a) B[tot]=B1-B2=0

B1= μ0I1/ 2π*0.15
B2= μ0I2/ 2π*0.05

μ0I1/ 2π*0.15 = μ0 I2/ 2π*0.05
6/0.15= I2/0.05
0.3=0.15 I2
I2=2A

b) ??

c)B=√B1^2+B2^2 (?)

Thank you very much for your help.

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nickjer
(b) Just do the same setup as you did for (a) except swap the distances for the two current carrying wires.

(c) Not sure what you are doing, but it is best if you draw the magnetic field lines from each wire at point S. That way you will know how to add the vectors.

ayalala
Thank you.

So basically for B it should be the same answer?

As for c:

If I understand correctly I need to "break" te view of each wire at point S and then:

B1(x access)=Bcosθ
B1(y access)=Bcosθ

then find vector for B1

same for B2