Magnetic field at the center of a semi-circle

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SUMMARY

The discussion focuses on calculating the magnetic field at the center of a semicircle with a radius of 3.2 cm, carrying a current of 6.4 A. The formula used is \(\overrightarrow{B}=\frac{\mu_0I}{2R}\), leading to the conclusion that the magnetic field at the center is \(\overrightarrow{B}=\frac{\mu_0I}{4R}\), resulting in a value of approximately \(4.4 \times 10^{-10}\) T. Participants emphasize the importance of the right-hand rule for determining the direction of the magnetic field, correcting initial misconceptions about the field's orientation.

PREREQUISITES
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  • Familiarity with the right-hand rule for magnetic field direction
  • Knowledge of the Biot-Savart Law and its application
  • Basic proficiency in using the permeability of free space (\(\mu_0\)) in calculations
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  • Study the application of the right-hand rule in complex current configurations
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vanillaatbest
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Homework Statement


1XizpjT.jpg

Find B at the center of the 3.2-cm-radius semicircle in the figure(Figure 1) . The straight wires extend a great distance outward to the left and carry a current I=6.4A.


Homework Equations


(Magnetic field for a current carrying loop)
\overrightarrow{B}=\frac{\mu_0I}{2R}


The Attempt at a Solution


  • Assuming that the two straight segments create magnetic fields that just cancel each other out, since their currents run opposite of each other.
  • Assuming the unshown segment somewhere far off to the left has insignificant influence (I think that's what "extend a great distance outward to the left" implies)

So I'm left with a semi-circle of radius .032 m and I need to find the magnetic field at the center.
Logically the field will just be half of that of a full circle, so:

\overrightarrow{B_\frac{1}{2}}=\frac{1}{2}\frac{\mu_0I}{2R}=\frac{\mu_0I}{4R}=\frac{8.8542\cdot 10^{-12}\cdot 6.4}{4\cdot 0.032}=4.4271\cdot 10^{-10}

Rounds to 4.4E-10 (Mastering Physics asks for two significant figures)

Program marks it as incorrect. I'm not sure where to go from here. I considered magnetic moment, but aside from halving the magnetic moment, I'm not sure what I could do.

Thanks in advance!
 
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Hello vanillaatbest. Welcome to PF!

vanillaatbest said:
Assuming that the two straight segments create magnetic fields that just cancel each other out, since their currents run opposite of each other.

You'll need to think about this more carefully. :smile: Remember the right hand rule for determining the direction of magnetic field produced by a current element.
 
Is this correct?
 

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vanillaatbest said:
Is this correct?

I'm not sure. It looks to me like the bottom part of your figure is correct, but the top part is not. But that could be that my brain is interpreting the 3D nature of the picture differently than you intended (like an optical illusion). :bugeye:

In the attached figure, consider the blue and green sections of current.

Can you state the direction of the magnetic field at the red dot due to the blue section? (In or out of the page?)

Similarly, for the green section.
 

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Thanks for helping TSny,
I believe the magnetic field of the blue section at the red dot would be coming out of the screen.

The green section would be into the screen.
 
vanillaatbest said:
Thanks for helping TSny,
I believe the magnetic field of the blue section at the red dot would be coming out of the screen.

Hmm. Take a look here and see if that makes you want to change your answer.
 
...oh god

I've been using my left hand
 
Ah. A common slip.
 
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Ok. So in this case both the green and blue section would generate mag fields that point INTO the screen.

The semi-circle would generate a mag field that points OUT of the screen.
 
  • #10
Wait nope. Used my left hand again. The semi-circle's mag field would also point INTO the screen.
 
  • #11
Thank you for your help TSny. I'm going to take a break. If I find a solution later, I'll post it.
 

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