Magnetic Field due to Time Dependent Current

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SUMMARY

The discussion focuses on calculating the magnetic field B around a long, straight copper wire with a sinusoidal current of sin(ωt) amperes. Using Ampere's Law, the relationship μI = ∮B•dl is established, leading to the conclusion that B can be expressed as B = μ(sin(ωt))/2πr for r > R. The conversation highlights the importance of recognizing the quasi-static approximation and the assumptions regarding the properties of copper, resistivity (ρ), and permittivity (ε) in the context of time-dependent currents.

PREREQUISITES
  • Understanding of Ampere's Law and its application in electromagnetism.
  • Familiarity with the Biot-Savart Law for magnetic field calculations.
  • Knowledge of sinusoidal functions and their implications in electrical circuits.
  • Basic concepts of resistivity (ρ) and permittivity (ε) in conductive materials.
NEXT STEPS
  • Study the derivation and applications of Ampere's Law in time-varying fields.
  • Explore the Biot-Savart Law and its use in calculating magnetic fields from current distributions.
  • Investigate the effects of resistivity and permittivity on current flow in conductors.
  • Learn about quasi-static approximations in electromagnetic theory and their limitations.
USEFUL FOR

Students and professionals in physics and electrical engineering, particularly those focusing on electromagnetism and circuit analysis involving time-dependent currents.

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Homework Statement


A long, straight, copper wire has a circular cross section with radius R, resistivity p and permittivity ε. If the current through the wire at any time t is sin(ωt) amperes, find the magnitude of the magnetic field B at time t a distance r from the centre of the wire for r > R.


Homework Equations


Ampere's Law:
μI = Bdl
Possibly Law of Biot-Savart:
B = μ/4π * (Idl x r)/r^2

The Attempt at a Solution


μI = Bdl
μ(sin(ωt))=∮B*dl (Since they are parallel)
μ(sin(ωt))=B∮dl (Since B is constant radially around conductor)

This is where I reach a bottleneck. I don't know how to incorporate ε (since this is a magnetic field). I assume resistivity would be used in calculating the current I, but I don't know how that ties into the sinusoidal function.
 
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maybe you don't need to use ##\epsilon## and ##\rho##. Also, you have already used a certain kind of assumption about ##\epsilon## and ##\rho## to get your answer. So maybe the question is hoping that you will explicitly state this assumption about ##\epsilon## and ##\rho##.

Your answer is essentially a kind of quasi-static approximation. (Not the most general answer for this question). But you have implicitly used the fact that copper is a good conductor, and assumed a certain relationship between ##\omega##, ##\epsilon## and ##\rho##. I'm not sure if that was your deliberate intention, or if you missed a few steps. But I think you have the answer they were looking for, but maybe without explaining under what approximation this answer will work.
 

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