Magnetic Field due to Time Dependent Current

  • Thread starter Mysterious
  • Start date
  • #1

Homework Statement


A long, straight, copper wire has a circular cross section with radius R, resistivity p and permittivity ε. If the current through the wire at any time t is sin(ωt) amperes, find the magnitude of the magnetic field B at time t a distance r from the centre of the wire for r > R.


Homework Equations


Ampere's Law:
μI = Bdl
Possibly Law of Biot-Savart:
B = μ/4π * (Idl x r)/r^2

The Attempt at a Solution


μI = Bdl
μ(sin(ωt))=B*dl (Since they are parallel)
μ(sin(ωt))=Bdl (Since B is constant radially around conductor)

This is where I reach a bottleneck. I don't know how to incorporate ε (since this is a magnetic field). I assume resistivity would be used in calculating the current I, but I don't know how that ties into the sinusoidal function.
 

Answers and Replies

  • #2
BruceW
Homework Helper
3,611
120
maybe you don't need to use ##\epsilon## and ##\rho##. Also, you have already used a certain kind of assumption about ##\epsilon## and ##\rho## to get your answer. So maybe the question is hoping that you will explicitly state this assumption about ##\epsilon## and ##\rho##.

Your answer is essentially a kind of quasi-static approximation. (Not the most general answer for this question). But you have implicitly used the fact that copper is a good conductor, and assumed a certain relationship between ##\omega##, ##\epsilon## and ##\rho##. I'm not sure if that was your deliberate intention, or if you missed a few steps. But I think you have the answer they were looking for, but maybe without explaining under what approximation this answer will work.
 

Related Threads on Magnetic Field due to Time Dependent Current

  • Last Post
Replies
9
Views
1K
  • Last Post
Replies
13
Views
881
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
2
Views
10K
Replies
0
Views
2K
  • Last Post
Replies
8
Views
6K
  • Last Post
Replies
10
Views
582
  • Last Post
Replies
4
Views
10K
  • Last Post
Replies
1
Views
647
  • Last Post
Replies
2
Views
579
Top