Magnetic field for a single-layer solenoid

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  • #1
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does anybody know why the magnetic field for a single-layer solenoid of a point in the middle of the solenoid axial field is
H=[(4pini)/(10L)]*{[L+2x/[2(D^2+(L+2x)^2]^(0.5) +
[L-2x/[2(D^2+(L-2x)^2]^(0.5)}
where L is the length of a finite solenoid, D is the diameter
 

Answers and Replies

  • #2
Physics Monkey
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You can calculate the on axis magnetic field of a current loop. To obtain the on axis field of a finite solenoid, just integrate.
 
  • #3
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i did.... i'm stuck on where does[(4pini)/(10L)] come from?
 

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