Magnetic field from two crossed current-carrying wires

[hardwork]

Homework Statement

Two long straight wires each carry 3.4 A of current and are crossed, as shown in the figure. If Dh=12.0cm and Dv=6.0cm, what is the magnitude and direction of the magnetic field at A? Figure: http://i41.tinypic.com/4louv6.jpg"

Homework Equations

B=(Mu)(I)/(2pie)(r)

The Attempt at a Solution

B = [(4pie x 10^-7 Tm/A)(3.4A)]/(2pie) x (1/6.0cm - 1/12.0cm)
B = 5.7 x 10^-8 T out of page

Would someone be able to please check if that is the correct answer? Thank you!

 

[Doc Al]

B = [(4pie x 10^-7 Tm/A)(3.4A)]/(2pie) x (1/6.0cm - 1/12.0cm)
B = 5.7 x 10^-8 T out of page

Almost. Express those distances in standard units.

 

[hardwork]

Oh, right. Thank you!

B = 5.7 x 10^-6 T out of page

 

[Doc Al]

B = 5.7 x 10^-6 T out of page

Good!