[SOLVED] Magnetic Field in a Rectangular Conducting Loop 1. The problem statement, all variables and given/known data Figure 31-64a shows a rectangular conducting loop of resistance R = 0.010 , height H = 1.5 cm, and length D = 2.5 cm being pulled at constant speed v = 55 cm/s through two regions of uniform magnetic field. Figure 31-64b gives the current i induced in the loop as a function of the position x of the right side of the loop. For example, a current of 3.0 µA is induced clockwise as the loop enters region 1. What are the magnitudes and directions of the magnetic field in region 1 and region 2? 2. Relevant equations [tex] EMF=BLV [/tex] [tex] i=EMF/R [/tex] 3. The attempt at a solution Okay, I found the magnetic field in region 1 like so: 3*10^-6A = EMF / 0.010 ohms EMF=3*10^-8 V 3*10^-8 V = B * 0.015m * 0.55 m/s B = 3.64 microT for region 1 However, for region 2 I must be making a mistake somewhere. Could someone point out my mistake please? Here's what I tried: -2*10^-6A = EMF/ 0.010 ohms EMF = 2*10^-8 V EMF=BLV 2*10^-8V = B * 0.55 m/s * 0.015m B=2.42 microT I have a feeling the mistake is in the length but I don't entirely understand how to interpret the problem statement. Thanks for your help!