Magnetic Field of 60-Turn Coil w/ 0.2m Radius & 4A Current

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SUMMARY

The magnetic field at the center of a 60-turn coil with a radius of 0.2 m carrying a current of 4 A is calculated using the formula B = (μ₀ * N * I) / (2 * r). In this equation, μ₀ represents the permeability of free space, N is the number of turns (60), I is the current (4 A), and r is the radius (0.2 m). The correct interpretation of the coil as a flat circular coil rather than a solenoid is crucial for accurate calculations.

PREREQUISITES
  • Understanding of electromagnetic theory
  • Familiarity with the formula for magnetic fields in coils
  • Knowledge of the permeability of free space (μ₀)
  • Basic algebra for manipulating equations
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pooka
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What is the magnetic field at the center of a 60-turn coil carrying a current of 4 A, if it has a radius of 0.2 m?

I was thinking of using the equation B=(mu0)(N/l)(current)

But I was wondering do I use the radius for l or do I use the diameter?
 
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I think you need to consider it as flat circular coil instead of a solenoid

B=\frac{\mu_0 NI}{2r}
 
thanks!
 

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