Magnetic Field of rectangular current loop

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Homework Help Overview

The discussion revolves around finding the magnetic field of a rectangular current loop positioned symmetrically in the xy-plane, specifically at the point (0,0,z). Participants are exploring the application of the Biot-Savart law and related formulas.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the Biot-Savart law and question the appropriateness of certain formulas for the given geometry. There are attempts to relate angles and distances to the magnetic field components, with some participants expressing uncertainty about their calculations.

Discussion Status

The discussion is ongoing, with participants providing various insights and questioning the assumptions made in their approaches. Some have suggested that symmetry may play a role in simplifying the problem, while others are still grappling with the correct application of the Biot-Savart law.

Contextual Notes

There is mention of the difficulty of the problem and the level of physics involved, indicating it is a third-year E&M course. Participants are encouraged to show more work to facilitate further discussion.

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Homework Statement



Find the magnetic field of a rectangular current loop lying symmetrically on the xy-plane. Find the magnetic field at (0,0,z)

Homework Equations



Biot-Savart law or derived formula (Mu/4*Pi) * sin(theta2)-sin(theta1)/s

The Attempt at a Solution


I am NOT good with getting my trianges correctly. I know that B1=B3 and B2=B4 but I cannot figure out the values of the thetas!
 
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Try and show a little more work than what you've got.
 
Well I know how to solve it for a square loop theta 1 =-theta2=45 degrees
= sqrt2*Mu*I/Pi*R
Now for a rectangle I think that theta1=-theta2 (for sides B1=B3) = -b/(sqrt(a^2+z^2)
and theta1=theta2 (for sides B2=B4) = a/(sqrt(b^2+z^2) and than I add them together but I'm not sure
 
Noone can help me with this question?
 
This is actually pretty tough. You're going to have to use the Biot-Savart law from scratch. The formula you're trying to use is for a point in the same plane as the wire, and isn't going to work here.

[tex]\mathbf{B}(\mathbf{r})=\frac{\mu_0 I}{4 \pi} \int \frac{d \mathbf{l}\times \hat{\mathbf{r}}}{r^2}[/tex]

You should realize some amount of symmetry. I remember I worked this out once, because I was making rectangular coils for a magneto-optical trap, and it took me a bit. What level of physics is this?
 
Last edited:
Mindscrape said:
This is actually pretty tough. You're going to have to use the Biot-Savart law from scratch. The formula you're trying to use is for a point in the same plane as the wire, and isn't going to work here.

[tex]\mathbf{B}(\mathbf{r})=\frac{\mu_0 I}{4 \pi} \int \frac{d \mathbf{l}\times \mathbf{r}}{r^2}[/tex]

You should realize some amount of symmetry. I remember I worked this out once, because I was making rectangular coils for a magneto-optical trap, and it took me a bit. What level of physics is this?

Slight modification: notice that it should read [tex]\mathbf{B}(\mathbf{r})=\frac{\mu_0 I}{4 \pi} \int \frac{d \mathbf{l}\times \mathbf{r}}{r^3}[/tex].
 
Oops, yeah, I forgot the hat, I'll fix mine and let yours be an alternate. :)

Edit: Nvm, the hat on the r vector isn't working... so the later version is the best.
 
It's third year...E&M 2..any help? I do know there is symmetry of the horizontal and vertical components, and they all add up to give the total magnetic field
 
Actually, I've been thinking about this. You can use the derived result that you mentioned earlier, or start from scratch from Biot-Savart. Either way, it's your homework and not mine. You have to make the effort. If you have, then show use you've made the effort by posting some work.
 

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