Magnetic Field of rectangular current loop

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SUMMARY

The discussion focuses on calculating the magnetic field of a rectangular current loop positioned symmetrically on the xy-plane, specifically at the point (0,0,z). Participants emphasize the use of the Biot-Savart law, represented by the formula B(r) = (μ₀ I / 4π) ∫ (dℓ × r) / r³, to derive the magnetic field. The challenge lies in determining the angles θ1 and θ2 for the rectangular configuration, with the symmetry of the loop being a crucial factor in the calculation. The conversation highlights the complexity of the problem, particularly for students in their third year of Electromagnetism (E&M 2).

PREREQUISITES
  • Understanding of the Biot-Savart law
  • Familiarity with magnetic fields generated by current-carrying conductors
  • Knowledge of vector calculus
  • Basic concepts of electromagnetism at the undergraduate level
NEXT STEPS
  • Study the derivation and application of the Biot-Savart law in different geometries
  • Explore the concept of magnetic field symmetry in current loops
  • Learn how to calculate magnetic fields for various shapes, including rectangular and circular loops
  • Review advanced topics in Electromagnetism, particularly in E&M 2 courses
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and anyone involved in experimental physics or engineering applications involving magnetic fields.

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Homework Statement



Find the magnetic field of a rectangular current loop lying symmetrically on the xy-plane. Find the magnetic field at (0,0,z)

Homework Equations



Biot-Savart law or derived formula (Mu/4*Pi) * sin(theta2)-sin(theta1)/s

The Attempt at a Solution


I am NOT good with getting my trianges correctly. I know that B1=B3 and B2=B4 but I cannot figure out the values of the thetas!
 
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Try and show a little more work than what you've got.
 
Well I know how to solve it for a square loop theta 1 =-theta2=45 degrees
= sqrt2*Mu*I/Pi*R
Now for a rectangle I think that theta1=-theta2 (for sides B1=B3) = -b/(sqrt(a^2+z^2)
and theta1=theta2 (for sides B2=B4) = a/(sqrt(b^2+z^2) and than I add them together but I'm not sure
 
Noone can help me with this question?
 
This is actually pretty tough. You're going to have to use the Biot-Savart law from scratch. The formula you're trying to use is for a point in the same plane as the wire, and isn't going to work here.

\mathbf{B}(\mathbf{r})=\frac{\mu_0 I}{4 \pi} \int \frac{d \mathbf{l}\times \hat{\mathbf{r}}}{r^2}

You should realize some amount of symmetry. I remember I worked this out once, because I was making rectangular coils for a magneto-optical trap, and it took me a bit. What level of physics is this?
 
Last edited:
Mindscrape said:
This is actually pretty tough. You're going to have to use the Biot-Savart law from scratch. The formula you're trying to use is for a point in the same plane as the wire, and isn't going to work here.

\mathbf{B}(\mathbf{r})=\frac{\mu_0 I}{4 \pi} \int \frac{d \mathbf{l}\times \mathbf{r}}{r^2}

You should realize some amount of symmetry. I remember I worked this out once, because I was making rectangular coils for a magneto-optical trap, and it took me a bit. What level of physics is this?

Slight modification: notice that it should read \mathbf{B}(\mathbf{r})=\frac{\mu_0 I}{4 \pi} \int \frac{d \mathbf{l}\times \mathbf{r}}{r^3}.
 
Oops, yeah, I forgot the hat, I'll fix mine and let yours be an alternate. :)

Edit: Nvm, the hat on the r vector isn't working... so the later version is the best.
 
It's third year...E&M 2..any help? I do know there is symmetry of the horizontal and vertical components, and they all add up to give the total magnetic field
 
Actually, I've been thinking about this. You can use the derived result that you mentioned earlier, or start from scratch from Biot-Savart. Either way, it's your homework and not mine. You have to make the effort. If you have, then show use you've made the effort by posting some work.
 

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