Magnetic Field of Two Wires where is zero

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Homework Help Overview

The problem involves determining the location along the y-axis where the magnetic field created by two parallel wires carrying currents in opposite directions is zero. The currents are specified as I1 = 49 A and I2 = 31 A, positioned at different heights on the y-axis.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the magnetic field contributions of each wire and explore the conditions under which these fields may cancel each other. There are attempts to set up equations based on the distances from a point to each wire, and questions arise regarding the correctness of these equations.

Discussion Status

The discussion is active, with participants sharing their thoughts on how to approach the problem. Some have suggested specific distances and locations to analyze, while others are clarifying their understanding of the relationships between the currents and distances involved. There is no explicit consensus yet, but guidance has been offered regarding how to set up the equations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can use or the methods they can apply. There is also a focus on ensuring that the distances and coordinates are correctly interpreted in relation to the wires.

hellogirl88
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Two wires carry current I1 = 49 A and I2 = 31 A in the opposite directions parallel to the x-axis at y1 = 7 cm and y2 = 15 cm. Where on the y-axis (in cm) is the magnetic field zero?


I don't even know where to start on this. Any help would be great!
 
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Consider the magnetic field of a wire carrying current:
where (+) is going into the page, and (.) is coming up out of the page.

(+) (+) (+) (+) (+) (+)
------------------------>
(.) (.) (.) (.) (.) (.)

If you add one going the other direction then:

(+) (+) (+) (+) (+) (+)
------------------------>
(.) (.) (.) (.) (.) (.)

(.) (.) (.) (.) (.) (.)
<------------------------
(+) (+) (+) (+) (+) (+)

So in between the fields reinforce. Which means to either side they may cancel somewhere - which is what you want.

With the B field given by B = μo*I/2π*R you need to construct an equation that describes where the fields are equal but opposite.
 
Well originally I was thinking μo*I1/2π*R = - μo*I2/2π*R, but I know this is wrong. Then I considered I1/R1 = - I2/R2, but I don't think this is right either...so I am still lost
 
You need to pick some location call it P outside the 2 wires. It will be a distance of D away from one wire and D + 8 cm away from the other. Now what you need to do is find where the fields are equal.

Use that in your I1/R1 = I2/R2
 
LowlyPion said:
You need to pick some location call it P outside the 2 wires. It will be a distance of D away from one wire and D + 8 cm away from the other. Now what you need to do is find where the fields are equal.

Use that in your I1/R1 = I2/R2

So say I pick P as Y = 17, so that point would be 2cm away from wire 1 and 10 cm away from wire 2...how do I use this information to find where the fields are equal?
 
hellogirl88 said:
So say I pick P as Y = 17, so that point would be 2cm away from wire 1 and 10 cm away from wire 2...how do I use this information to find where the fields are equal?

No, no, no.

Say you pick R1 as D and R2 as 8 cm + D, and then solve for what D is.
 
Ok, so I did 49/D = 31/D+8 and solved for D...is this value supposed to be where on the Y axis the magnetic field is zero?
 
hellogirl88 said:
Ok, so I did 49/D = 31/D+8 and solved for D...is this value supposed to be where on the Y axis the magnetic field is zero?

It's not the Y coordinate value. It's the distance from the 49A laden wire. You will have to make a drawing and determine what that y coordinate value would be.

Note: Since you chose D as from the 49 you should expect that the (-) value you get is in the direction of the 31A wire and to the other side of it.
 
I finally got it. Thank you so much for your help
 

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