How Does an Antiproton Accelerate in Combined Electric and Magnetic Fields?

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SUMMARY

The discussion focuses on calculating the acceleration of an antiproton moving in combined electric and magnetic fields. Given the parameters, the antiproton has a velocity of 500 m/s, a magnetic field strength of 2.5 T, and an electric field strength of 1000 V/m. The correct calculation for the antiproton's acceleration results in a magnitude of 2.4 x 1010 m/s2. The participant initially attempted to use the formula F = ma and F = qvB but did not account for the electric field's influence.

PREREQUISITES
  • Understanding of classical mechanics, specifically Newton's second law (F = ma).
  • Knowledge of electromagnetic theory, particularly the Lorentz force law (F = q(E + v x B)).
  • Familiarity with the properties of antiprotons and their charge (q = -e).
  • Basic proficiency in vector mathematics to analyze forces in different directions.
NEXT STEPS
  • Study the Lorentz force law in detail, focusing on the interaction of electric and magnetic fields.
  • Learn about particle dynamics in electromagnetic fields, particularly for charged particles like antiprotons.
  • Explore the implications of relativistic effects on particle acceleration in high-energy physics.
  • Review practical applications of antiproton acceleration in particle physics experiments and accelerators.
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism and particle dynamics, as well as researchers involved in high-energy particle physics and accelerator technology.

ursulan
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Homework Statement


An antiproton (same properties as a proton except that q=-e) is moving in the combined electric and magnetic fields of the figure

The antiproton is moving to the right with a velocity of 500m/s the magnetic field B=2.5T is coming into the page and E=1000V/m downward.

What is the magnitude of the antiproton's acceleration at this instant?

Homework Equations



F=ma, F=qvB

The Attempt at a Solution



The answer is 2.4x10^10m/s^2. I bascially went ma=qvB which didn't work. I'm not sure why it shows E.
 
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ursulan said:

Homework Statement


An antiproton (same properties as a proton except that q=-e) is moving in the combined electric and magnetic fields of the figure

The antiproton is moving to the right with a velocity of 500m/s the magnetic field B=2.5T is coming into the page and E=1000V/m downward.

What is the magnitude of the antiproton's acceleration at this instant?

Homework Equations



F=ma, F=qvB

The Attempt at a Solution



The answer is 2.4x10^10m/s^2. I bascially went ma=qvB which didn't work. I'm not sure why it shows E.

Maybe this will help?
http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magfor.html#c2
 

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