Magnetic field two parallel wires

[goWlfpack]

Homework Statement

Two parallel wires are separated by 5.30 cm, each carrying 2.5 A of current in same direction. What is the magnitude of the force per unit length between the wires?

Homework Equations

B2=(mo constant)I2/2pid

The Attempt at a Solution

plugged 2.5 in for I and .053 for d
red x
help?

 

[Defennder]

That equation isn't enough You need the equation for the force on a current carry conductor due to a magnetic field.

 

[baba89]

The magnitude of the force per unit length between the two parallel wires can be calculated using the formula F = (μ0/2π) * (I1 * I2)/d, where μ0 is the permeability constant, I1 and I2 are the currents in the two wires, and d is the distance between the wires.

Plugging in the given values, we get F = (4π x 10^-7 N/A^2) * (2.5 A * 2.5 A)/0.053 m = 4.72 x 10^-5 N/m.

This means that for every meter of wire, there will be a force of 4.72 x 10^-5 N acting between them. This force is attractive, as the currents in the wires are in the same direction.

Note: It is important to use consistent units in the calculations. In this case, the distance between the wires (d) is given in centimeters, so it should be converted to meters (0.053 m) before plugging it into the formula.