Magnetic field two parallel wires

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SUMMARY

The discussion focuses on calculating the force per unit length between two parallel wires carrying a current of 2.5 A each, separated by a distance of 5.30 cm. The relevant equation for the magnetic field generated by one wire is given as B2 = (μ₀ * I2) / (2 * π * d). However, to find the force between the wires, the equation F/L = I * B must be utilized, where F is the force, L is the length of the wire, I is the current, and B is the magnetic field produced by the other wire.

PREREQUISITES
  • Understanding of Ampère's Law
  • Familiarity with the Biot-Savart Law
  • Knowledge of magnetic fields generated by current-carrying conductors
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of the force between parallel conductors using F = I * B
  • Learn about the application of Ampère's Law in calculating magnetic fields
  • Explore the Biot-Savart Law for magnetic field calculations
  • Investigate the effects of varying current and distance on the force between wires
USEFUL FOR

Physics students, electrical engineers, and anyone interested in understanding electromagnetic interactions between current-carrying conductors.

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Homework Statement



Two parallel wires are separated by 5.30 cm, each carrying 2.5 A of current in same direction. What is the magnitude of the force per unit length between the wires?


Homework Equations



B2=(mo constant)I2/2pid

The Attempt at a Solution


plugged 2.5 in for I and .053 for d
red x
help?
 
Physics news on Phys.org
That equation isn't enough You need the equation for the force on a current carry conductor due to a magnetic field.
 

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