Magnetic fields and induced EMF

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SUMMARY

The discussion focuses on calculating the induced electromotive force (emf) in a coil with 4000 turns and a cross-sectional area of 25 cm² when a magnetic field of flux density 0.16 T is reduced to zero over 0.0050 seconds. The correct formula for induced emf is E = -N (dΦ/dt), where Φ represents magnetic flux. The accurate calculation yields an induced emf of -1.28 MV, confirming that proper unit conversion for area is crucial, as 25 cm² equals 0.0025 m², not 0.25 m².

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with magnetic flux and its calculation
  • Knowledge of unit conversions, particularly area from cm² to m²
  • Basic proficiency in algebra for manipulating equations
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  • Study the principles of Faraday's Law in detail
  • Learn about the applications of induced emf in electrical circuits
  • Explore advanced topics in electromagnetic theory, such as Lenz's Law
  • Investigate practical experiments demonstrating electromagnetic induction
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Homework Statement


An coil has 4000 turns of wire and a mean area of cross-section 25cm^2. A magnetic field of flux density 0.16T passes through it. When the magnetic field is reduced steadily to zero in 0.0050s, emf is induced across the terminals of the coil. Calculate the value of this induced emf.



Homework Equations



E = N D Φ /Dt


The Attempt at a Solution



E = 4000 X (0.25 X 0.16) ÷ 0.0050 = 32 X 10^3V?

Or here's another solution
Ɛ = - N∆Φ / ∆t


25 cm² = 25 x 10^-4 m²

Φ = NBA = 4000 turns x 0.16 T x (25 x 10^-4 m²) = 1.6 Wb

Ɛ = - (4000 turns x 1.6 Wb) / 0.0050 s = - 1.28 x 10^6 V or - 1.28 MV

Please help. The second one seems more logical however I'm not sure its right. Thanks
 
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Your initial equation can be used to solve the problem:

emf=-N\frac{d\Phi}{dt}

You are making an error though. You are not converting the area units correctly.

25cm^2=0.0025m^2

not 0.25m^2
 
Last edited:

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