Calculating Magnetic Flux in a Solenoid-Loop System with Varying Angles

Click For Summary

Homework Help Overview

The discussion revolves around calculating magnetic flux in a system involving a solenoid and a loop, specifically addressing scenarios where the loop is oriented at different angles relative to the magnetic field produced by the solenoid.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate magnetic flux for two different orientations of the loop, questioning the application of the cosine function in their calculations. Some participants raise concerns about the assumptions regarding the magnetic field outside the solenoid.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem setup and the implications of the magnetic field's behavior outside the solenoid. There is no explicit consensus on the correct approach or calculations at this stage.

Contextual Notes

Participants are working under a time constraint, as the problem is due soon, and there is uncertainty regarding the magnetic field's uniformity outside the solenoid.

BuBbLeS01
Messages
602
Reaction score
0
Magnetic flux...help please!

Homework Statement


A 2.02-cm-diameter solenoid passes through the center of a 8.62-cm-diameter loop. The magnetic field inside the solenoid is 0.75 T.
A.) What is the magnetic flux through the loop when it is perpendicular to the solenoid?
B.) What is the magnetic flux through the loop when it is tilted at a θ=60° angle? (60 degrees from the y-axis)

Homework Equations


MF = AB cosθ


The Attempt at a Solution


A.) wouldn't it just be zero since cos90 = 0? or is it not 90 degrees?
B.) A = (0.0862/2)^2 * pi = 0.00584
0.00584 * 0.75 * cos 60 = 0.002188
and I am getting that wrong as well
 
Physics news on Phys.org
can anyone help me with this?
 
does anyone know how to do this...it's due today and I still am not getting it right...
 
I'm not certain what your exact setup is. can you ignore the magnetic field on the outside of the solenoid? It won't be equal to 0.75 T there.
 

Similar threads

Replies
3
Views
2K
Replies
4
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 37 ·
2
Replies
37
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
9K
Replies
4
Views
2K