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Magnetic flux through the circular cross-sectional area of the solenoid

  1. Mar 1, 2010 #1
    1. The problem statement, all variables and given/known data
    A solenoid 1.7 cm in diameter and 30 cm in length has 4000 turns and carries a current of 5 A. Calculate the magnetic flux(in Wb) through the circular cross-sectional area of the solenoid. Since this is a very long solenoid, you may use the simplified magnetic field formula for the infinite solenoid.


    2. Relevant equations
    B = µ * N * I


    3. The attempt at a solution
    B = (4 . π . 10^–7) . (4000 / 0.3) . 5 = 8.4 . 10^–2 T


    My online homework is telling me this is incorrect. Im not sure what im doing wrong.
     
  2. jcsd
  3. Mar 1, 2010 #2

    collinsmark

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    Hello Kourtney0115,

    It seems you've already calculated the magnetic field (measured in Teslas). Next step is to find the magnetic flux (measured in Webers).
     
  4. Mar 1, 2010 #3
    Im not sure how to convert T into Wb. I tried to look it up on google and the only thing i found was T=Wb/m^2. But i am not given m^2.
     
  5. Mar 1, 2010 #4

    collinsmark

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    Magnetic flux is the magnetic field integrated over some surface (which has an area). For the special case where magnetic field is constant over a given area (surface), the the magnetic flux through that surface is the dot product of the magnetic field and the surface (the "surface" being something which has a surface area).

    Hint: The problem statement says, "...through the circular cross-sectional area of the solenoid."
     
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