Magnetic Force Exerted on Particle

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SUMMARY

The discussion centers on calculating the magnetic force exerted on a charged particle with a mass of 6.64e-27 kg and a charge of +3.2e-19 C, which is accelerated through a potential difference of 2.45e6 V before entering a 1.6-T magnetic field. The correct formula for magnetic force is given by F = qvB, where F is the magnetic force, q is the charge, v is the velocity, and B is the magnetic field strength. The calculated magnetic force is 7.87e-12 N, confirming the accuracy of the provided answer.

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  • Understanding of classical mechanics and electromagnetism
  • Familiarity with the concepts of electric potential and kinetic energy
  • Knowledge of the Lorentz force equation
  • Basic proficiency in algebra and unit conversions
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moebiusatg
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Sorry for slightly disregarding the proper format but I'm really quite lost so I can abide by what is expected. However I will be detailed

Question is: A particle with a mass of 6.64e-27 kg and a charge of +3.2e-19 C is accelerated from rest through a potential difference of 2.45e6 V. The particle then enters a uniform 1.6-T magnetic field. If the particle's velocity if perpendicular to the magnetic field at all times, what is the magnitude of the magnetic force exerted on the particle?

I'm unsure how to start this problem but I know the answer is 7.87e-12 N.

Any help is greatly appreciated.

Thanks!
 
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Please include any relevant equations you are aware of. What is the formula for force exerted by a magnetic field?
 

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