Magnetic Force in a current carrying coil

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SUMMARY

The discussion centers on calculating the magnetic force acting on a rectangular loop with dimensions 0.30 m by 0.12 m and a mass of 25 grams as it enters a magnetic field. The initial speed of the loop is calculated using the formula v = √(2gd), yielding a speed of 2.34 m/s. The magnetic force is determined to be equal to the gravitational force, calculated as F = mg = 245.25 N, indicating that the forces are balanced at constant velocity. The subsequent calculations for the magnetic field strength and induced current depend on this established magnetic force.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with electromagnetic principles, specifically Faraday's law of induction
  • Knowledge of basic physics equations, including F = ma and the relationship between force, mass, and acceleration
  • Ability to perform calculations involving gravitational force and magnetic fields
NEXT STEPS
  • Research Faraday's law of electromagnetic induction
  • Learn how to calculate magnetic field strength using the formula B = F/(ILsinθ)
  • Explore the relationship between induced current and magnetic flux
  • Study the effects of resistance in circuits, particularly in relation to induced current
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of electromagnetism and the dynamics of current-carrying coils in magnetic fields.

nhartung
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Homework Statement


A rectangular loop with length of l = 0.30 m and width w = 0.12 m and a mass of 25-grams falls (from rest) a distance of .28 m before entering a constant magnetic field that points out of the page. The internal resistance of the wire is 5.5 \Omega.

(i) What is the speed of the loop when it first enters BOut. (The magnetic field).

Here I think i can just use v = \sqrt{2gd} = 2.34 m/s. (correct me if this is an incorrect way of finding this.)

(ii) If, while the loops enters the magnetic field, it moves at a constant speed, then what is the magnetic force.

Here I'm stuck but I am thinking there is just some equation that I am missing but I've been searching my book and haven't found anything helpful.

(iii) What is the magnitude of the magnetic field BOut.

(iv) What is the magnitude of the induced current.

I'm thinking I can use I = \frac{LBsinø}{F} for this..

I just want to focus on (ii) right now because I think (iii) and (iv) depend on (ii)'s answer and hopefully are easy.
 
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Ok I think I've worked out (ii) Since the loop has constant velocity this means the acceleration is zero. This must mean the Force of Gravity and Magnetic Force are canceling each other (they are equal) which means F = mg = 245.25N. I still need some help on (iii) and (iv) though.
 

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