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Magnetic Force on an a Particle

  1. Apr 20, 2009 #1
    1. The problem statement, all variables and given/known data

    A particle with a charge of 35.7 uC moves with a speed of 61.1 m/s in the positive x direction. The magnetic field in this region of space has a component of 0.527 T in the positive y direction, and a component of 0.820 T in the positive z direction. What is the magnitude of the magnetic force on the particle?

    2. Relevant equations
    magnetic F=[q]vB
    electric F=qE


    3. The attempt at a solution
    I really do not know what I am doing and need help
    Here is an attempt:

    F=qvB
    (3.57 e-6 C)(61.1 m/s)(0.527 T)= 1.1495 e-4 N???
     
  2. jcsd
  3. Apr 20, 2009 #2

    Cyosis

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    It is almost correct, however you took the wrong value for B. What is the magnitude of B?
     
  4. Apr 20, 2009 #3
    ok! SO I figured it out! You use pathagoreum Theorem and you end up getting that
    B= 0.9756 T
    I pluged that in and got the answert to be: 2.13 e-3 N

    NOW though I don't understand what they are asking for when they ask:
    What is the direction of the magnetic force on the particle relative to the positive z-axis???
    is it just the + or - infront of the value I recieved for the force? Or is there a completely different asnwer?
     
  5. Apr 20, 2009 #4

    Cyosis

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    Do you know how to determine the direction of the magnetic force when given the direction of v and B? Just draw a picture so you can see how the vector is placed with respect to the z-axis.
     
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