1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Magnetism: Forces between two parallel wires

  1. Dec 2, 2014 #1
    1. The problem statement, all variables and given/known data
    Two long, straight wires with a current of 8.2A on the left and 9.3A on the right flowing in the same direction. The distance between the wires is 8.8 cm.

    a) What is the magnitude of the force per unit length between these two wires both in length and direction
    b) How far to the right of the 8.2A wire is the magnetic field due to both currents 0?
    c) Now a charge is placed 5.3cm from the 9.3 A current, moving to the right at 76.6 m/s, the charge is 2.9x10^-6C, What is the magnitude of the total magnetic force on this charge

    2. Relevant equations

    magcur3.gif
    F=qvBsin(theta)

    3. The attempt at a solution

    For part a I simply used the first formula with using the radius of 0.088m, I is (9.3*8.2), and pretty much just fill in numbers, for an answer I got 1.7x10^-4 N/m, and the wires are attracted. This wasn't difficult.

    For part b I used the first formula and set I1=i2, where I1 is the 8.8 current (to the left) and I2 is the 9.3 current, to the right. The denominator in the equation for the field from I1 is 0.088-r, and for the denominator of I2 it was simple r.
    Using this method I achieved a distance of r=0.0452m, which seems to make sense to me as it should be somewhere sort of near the middle of the two wires-- using the curly right hand rule I can tell that the field from both of these wires will negate somewhere in the middle of the two wires and since they are close in magnitude it should therefore be in the center. I am just unsure of my method here. I think from a conceptual standpoint I understand what is happening but I am unsure of my math.

    For part c I used the principle of super position to add the two magnetic fields together, using the curly right hand rule I assumed the fields would be adding together and not subtracting. This gave me my magentic field for F=qvB.. I als assumed that because the charge is directly right of the 9.3 charge that it is normal to the two wires and therefore receives the full effect of the field. I plugged the values in which resulted in a force of 1.04x10^-8 N

    I hope I am on the right track but this is a big question with room for error and I am new to magnetism. Thank you.
     
  2. jcsd
  3. Dec 2, 2014 #2

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    You mean 8.2, right?
    You are asked for the distance from the 8.2A. Isn't that your I1?
    Hmm... but how far from the other wire? Is it between them, to the right of the 9.3A, or out of the plane of the wires?
     
  4. Dec 3, 2014 #3
    My apologies, I will edit the OP. I1 is 8.2A, I2 is 9.3 A, and the distance between the two is 0.088m.

    The charge is moving right, and its original location is to the right of i2, at a distance of 0.053cm from I2
     
  5. Dec 3, 2014 #4

    haruspex

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    I don't see the correction. It still seems to me your r is the distance from I2, not I1. Are you still getting 0.0452m as the answer?
    Then your method is fine. I'll check the numbers if you post all your working.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Magnetism: Forces between two parallel wires
Loading...