Magnetomotive force and the H-field

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SUMMARY

The discussion centers on the relationship between magnetomotive force (MMF) and the H-field, specifically the equation \(\int H \cdot d\ell = F\). Participants clarify that while MMF is expressed as a force, it does not conform to traditional force measurements in Newtons. The confusion arises from the interpretation of the H-field, where multiplying it by a length \(\ell\) yields a current \(I\) instead of a force. The equation \(\int H \cdot d\ell = I\) is also highlighted, emphasizing the distinction between MMF and conventional forces.

PREREQUISITES
  • Understanding of the H-field in electromagnetism
  • Familiarity with the concept of magnetomotive force (MMF)
  • Basic knowledge of integrals in physics
  • Knowledge of the relationship between current and magnetic fields
NEXT STEPS
  • Study the derivation of the H-field and its applications in electromagnetism
  • Explore the concept of electromotive force (EMF) and its comparison to MMF
  • Investigate the mathematical implications of \(\int H \cdot d\ell\) in circuit analysis
  • Learn about the SI units and dimensional analysis related to magnetic fields
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in the principles of electromagnetism and the mathematical relationships between magnetic fields and currents.

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Homework Statement



The magnetomotive force is given as an integral of the H-field. I want to know how this can be a force.

Homework Equations



[tex]\int H \cdot d \ell = F[/tex]

The Attempt at a Solution



So a bit confused. Wiki says that this equation

[tex]\int H \cdot d \ell = F[/tex]

is a force, the magneto-motive-force. But this is the H-field multiplied by a length [tex]\ell[/tex]. From what I knew about the H-field, if you multiply the H-field with a length, you should get a current, not a force as

[tex]\int H \cdot d\ell = I[/tex]

I know this because

[tex]H = \frac{I}{2\pi r}[/tex]

you can see why by rearranging it

[tex]H \cdot r = \frac{I}{2\pi}[/tex]

so what gives?

Thanks in advance.
 
Physics news on Phys.org
It's analogous to electromotive force. Neither electromotive force or magnetomotive force is a force in the traditional sense. That is, it's not measured in Newtons in the SI unit system.
 

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