Magnetostatics - force on wire

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SUMMARY

The discussion focuses on calculating the magnetic force on a segment of wire carrying a current of 20 A in a magnetic field of 51 mT. The force is determined using the formula Fb = ILBsin(theta), where L is the length of the wire segment. The user initially attempted to calculate the force using only the length of the wire along the z-axis (7.2 m) but later realized that the total length of the wire segment (7.2 m + 6 m) must be considered. Additionally, a related question about a proton moving through a magnetic field is posed, emphasizing the use of the same fundamental equation to find the angle between the proton's velocity and the magnetic field.

PREREQUISITES
  • Understanding of magnetic fields and forces, specifically in the context of current-carrying wires.
  • Familiarity with the formula Fb = ILBsin(theta) for calculating magnetic force.
  • Knowledge of basic physics concepts such as current, magnetic field strength, and wire length.
  • Ability to manipulate trigonometric functions to solve for angles in physics equations.
NEXT STEPS
  • Review the derivation and applications of the formula Fb = ILBsin(theta).
  • Learn about the right-hand rule for determining the direction of magnetic forces on current-carrying wires.
  • Explore the effects of varying magnetic field strengths on the force experienced by a wire.
  • Investigate the relationship between velocity, magnetic fields, and forces on charged particles, specifically using Lorentz force equations.
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of magnetostatics and the forces acting on current-carrying conductors.

victorlee2
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Homework Statement


A segment of wire carries a current of 20 A
along the x-axis from x = −6 m to x = 0 and
then along the z axis from z = 0 to z = 7.2 m.
In this region of space, the magnetic field is
equal to 51 mT in the positive z direction.
What is the magnitude of the force on this
segment of wire?



Homework Equations


Fb= ILBsintheta



The Attempt at a Solution


Fb = ( 20 A ) (7.2m ) ( .051m )

the question asked for " the magnitude of the force on THIS SEGMENT of wire" so i thought to just plug in 7.2m but it turned out to be wrong so i added the 6m as well but it was wrong again. help =[
 
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i have another question

A proton moving at 1.2 × 106 m/s through a
magnetic field of 4.3 T experiences a magnetic
force of magnitude 4.9 × 10−13 N.
The charge of proton is 1.60218 × 10−19 C
and the mass of proton is 1.67262 × 10−27 kg.
What is the angle between the proton’s
velocity and the field?
Answer in units of ◦.

Is this question simply just plugging the values into Fb = BILsintheta and solve for theta? it seems too easy to be true.
 

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