Magnetostatics - Magnetic Flux + Force

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SUMMARY

The discussion focuses on the application of Ampère's Law to derive the magnetic field produced by a cylindrical wire and the calculation of magnetic flux through a surface S. The magnetic flux is expressed as the integral of the magnetic field B over the surface, specifically using cylindrical coordinates. The confusion arises from the choice of coordinate system and the symmetry of the problem, which is clarified by emphasizing the use of cylindrical coordinates and the phi-symmetry in the calculations.

PREREQUISITES
  • Understanding of Ampère's Law in magnetostatics
  • Familiarity with cylindrical coordinates in vector calculus
  • Knowledge of magnetic flux and its mathematical representation
  • Basic concepts of magnetic fields and their sources
NEXT STEPS
  • Study the derivation of magnetic fields using Ampère's Law in various geometries
  • Learn about the application of cylindrical coordinates in electromagnetism
  • Explore the concept of magnetic flux and its calculation in different coordinate systems
  • Investigate the implications of symmetry in electromagnetic problems
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Students of electromagnetism, physics educators, and anyone seeking to deepen their understanding of magnetostatics and magnetic field calculations.

jegues
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Homework Statement



See figure attached.

Homework Equations





The Attempt at a Solution



I can follow how he applies amperes law to obtain the magnetic field produce by the wire but I'm extremely confused how he writes the expression for the flux flowing through S.

What I understand to be the magnetic flux flowing through a surface S.

[tex]\int_{S}\vec{B}\cdot\vec{dS}[/tex]

Since the wire is a cylinder I assume cylindrical coordinates.

[tex]B = \mu_{0}H[/tex]

[tex]dS = rdrd\phi[/tex]

My integral seems to be quite a bit different than his.

Can someone clarify the steps to getting his integral, and why he chooses to work in the yz plane?

Thanks again!
 

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He exploits the phi-symmetry from the beginning while your surface element implies you do not. Perhaps if you showed your integral as how you constructed it I could be specific.

He does not do any of his work in the z-y plane. He shows you a cross-section in the z-y plane because that shows the symmetry of the situation most clearly. Try drawing the situation in the z-x ir x-y planes and you'll see this. He does his work entirely in cylindrical coords - you can see this in his integral over r. The z coord is the factor of d and phi is accounted for in the expression for Hphi.
 

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