A converging lens with a focal length of 14.2 cm is used to inspect a coin. The lens forms a virtual image 30.1 cm away. What is the magnification?
(1/Si) + (1/So) = (1/f)
M = (hi/ho) = (-Si/So)
The Attempt at a Solution
1/So = 1/f - 1/Si
1/(1/So) = So = 26.88cm
M = (-Si/So) = -30.1/26.88 = 1.12
I'm pretty sure that I have the solution and answer correct, but I just wanted to double check. This homework is online and the site is telling me that I have the answer wrong and I just wanted to make sure that I wasn't missing anything before I bother my teacher about it. As of right now I think it's just an error in the code of the site, but I'm just double checking. Thanks.