Magnitude and Direction of a charge interaction

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Homework Help Overview

The discussion revolves around determining the direction of the force on a -10 nC charge due to other charges, specifically focusing on calculating the angle of this force in a clockwise direction from the positive x-axis. The problem is situated within the context of electrostatics, as described in a physics textbook.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the angle using trigonometric functions after determining the force's magnitude. They express confusion regarding the clockwise and counterclockwise angle measurement.

Discussion Status

Participants are engaged in clarifying the coordinate system and the components of the forces acting on the charge. Some guidance has been offered regarding the components of the forces, and there is an ongoing exploration of the calculations involved.

Contextual Notes

There is a request for a visual representation of the coordinate axes and forces, indicating that the original poster may be missing some information or context needed for a complete understanding. The discussion also highlights potential confusion regarding the direction of angle measurement.

themonk
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Homework Statement


26.P39.jpg

What is the direction of the force [tex]\vec{F}[/tex] on the -10 nC charge in the figure? Give your answer as an angle measured cw from the +x-axis. Problem 26.39 in Physics for Scientists and Engineers Second Edition by Knight
Magnitude of the force is 4.3E-3 N

Homework Equations



As far as I know, this is the only relevant equations:

[tex]\vec{F}[/tex]=[tex]k*q_{1}*q_{2}/d^{2}[/tex]

The Attempt at a Solution


I already found the magnitude as listed above. But I need to find [tex]\theta[/tex] in the clockwise direction.

The force of A (being the -5 nC charge) I figured was direction -4.3E-4 [tex]\hat{j}[/tex] and -1.28E-3 [tex]\hat{i}[/tex] and the other charge had a force of -4.5E-3 I double checked with an answer from someone else (MasteringPhysics also said it was correct). I figured I would use a trigonometric function for the final part, ie the angle measured in the clockwise direction. In lab we used tangent, but was confused as to why (tangent is opposite over adjacent):

tan([tex]\theta[/tex])=4.07E-3/1.28E-3 ==> [tex]\theta[/tex]=tan[tex]^{-1}[/tex](3.179)

which is 72.54 degrees. I added 180 to it to get 252.54, but apparently that is not correct (I don't completely understand the cw and ccw part).

Is there any line of thought that I should proceed with?

(sorry about my English)
 
Last edited:
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Show the coordinate axes and the forces in your figure, please.

ehild
 
I can't edit the problem, but the x-axis ([tex]\hat{i}[/tex]) is left-right and the y-axis ([tex]\hat{j}[/tex]) would be up-down, if I am not mistaken. The origin would then be at the -10nC.
 
In this case the force on the -10 nC charge from the -5 nC one has only y component, and that form the 15 nC charge has both x and y components. Check your calculation and text.

ehild
 

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