- #1

Sipko

- 11

- 1

## Homework Statement

What is E in Magnitude and Direction at the center of the square of (fig. 3-7). Assume that q = 10x10

^{-8}C and a = 5 cm

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Now I have am not well versed with vectors, I don't like them and they don't like me.

I can not figure out the directions the magnitudes move in.

## Homework Equations

r=1/2(√2 a) = a/√2

E=k*q/r

^{2}

E

_{Total}= E

_{1}+ E

_{2}+ E

_{3}+ E

_{4}

## The Attempt at a Solution

So far I only managed to do this:

r= 5.0cm/√2 = 3.55*10

^{-2}

E

_{-q}=(8.99*10

^{9})*((-1.0*10

^{-8}C)/(3.55*10

^{-2}m)) = 7.13*10

^{4}N/C

E

_{2q}=(8.99*10

^{9})*(2*(-1.0*10

^{-8}C)/(3.55*10

^{-2}m)) = 1.43*10

^{5}N/C

And since the other magnitudes are the same I don't need to calculate the others.

So the next step involves knowing exactly which angles you need to calculate everything together. And that's what is giving me trouble.

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