Magnitude and Direction Word Problem

Click For Summary
SUMMARY

The discussion focuses on a navigation problem involving vector components and the Pythagorean theorem. The pilot initially flies 45 miles west, then 20 miles at 15° east of south. To determine the distance and direction back to the original destination, participants emphasize the need to calculate the x and y components of each leg of the journey. The correct application of trigonometric functions and the Pythagorean theorem is essential for finding the resultant vector and the total distance flown beyond the original flight plan.

PREREQUISITES
  • Understanding of vector components in physics
  • Proficiency in trigonometric functions, specifically sine and cosine
  • Familiarity with the Pythagorean theorem
  • Ability to interpret angles in standard position
NEXT STEPS
  • Calculate vector components for angles using sine and cosine functions
  • Learn how to apply the Pythagorean theorem to find resultant vectors
  • Study the concept of direction using inverse tangent (arctan) functions
  • Explore practical applications of vector addition in navigation scenarios
USEFUL FOR

Students in physics or mathematics, pilots, navigators, and anyone interested in solving real-world vector problems.

slu1986
Messages
36
Reaction score
0
1. The pilot of a small plane finds that the airport where he intended to land is fogged in. He flies 45 miles west to another airport to find that conditions there are too icy for him to land. He flies 20 miles at 15° east of south and is finally able to land at the third airport.

(a) How far and in what direction must he fly the next day to go directly to his original destination?

(b) How many extra miles beyond his original flight plan has he flown?


3. I know that you have to solve get the x and y components and plug them into the pythagorean theorem to get the resultant. And then do the arc tangent y/x to get the direction in degrees. I am just confused at how to set everything up. I figure that the x component of the 1st position is -45 mi since he is going west. and y - component is the sin (15) 20 mi = 5.17 mi. and plug these numbers into the pythagorean theorum = sqrt of -45^2 + 5.17^2 = 45.3 mi <---but i know this isn't right..So can someone please help me out and explain what I'm doing wrong and what I must do to do it correctly
 
Physics news on Phys.org
For the second leg, 20 miles at 15o East of South the vector has both x and y components. What are they? Drawing a diagram of the whole trip should help.
 
Take another look at the first leg, especially the y-component. As I read the problem, the first leg is due west.
 

Similar threads

Replies
5
Views
17K
  • · Replies 2 ·
Replies
2
Views
10K
Replies
5
Views
4K
Replies
1
Views
2K
  • · Replies 17 ·
Replies
17
Views
15K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 6 ·
Replies
6
Views
10K
Replies
2
Views
5K
  • · Replies 7 ·
Replies
7
Views
6K
Replies
2
Views
1K