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Magnitude of Cable Tensions and Compressive Force

  • #1

Homework Statement


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There's a diagram with a rough free body diagram implemented.


Homework Equations



This is what I'm really unsure about.


The Attempt at a Solution



Finding Compression at BC: mg*sin(60) = 8495N
Tension AC = mg*cos(25) = 8890N

Not sure if that's right, but, it's all I can come up with!

Please help!!
 

Answers and Replies

  • #2
6,054
390
At point C, what is the direction of:

1. The reaction force of the beam?
2. The reaction force of the upper part of the cable?
3. The force applied by the lower part of the cable?
 
  • #3
How do I find them?
 
  • #4
6,054
390
Each of those has only two possibilities. Consider both, choose one that makes physical sense.
 

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