Magnitude of Cable Tensions and Compressive Force

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nobodyuknow
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Homework Statement


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There's a diagram with a rough free body diagram implemented.


Homework Equations



This is what I'm really unsure about.


The Attempt at a Solution



Finding Compression at BC: mg*sin(60) = 8495N
Tension AC = mg*cos(25) = 8890N

Not sure if that's right, but, it's all I can come up with!

Please help!
 
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At point C, what is the direction of:

1. The reaction force of the beam?
2. The reaction force of the upper part of the cable?
3. The force applied by the lower part of the cable?
 
Each of those has only two possibilities. Consider both, choose one that makes physical sense.