Magnitude of centripetal force acting on a roller coaster at the top of a loop

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SUMMARY

The discussion centers on calculating the magnitude of the centripetal force acting on a roller coaster at the top of a vertical loop. The minimum speed required for the roller coaster to maintain its trajectory is critical, as it determines the forces acting on it. At this point, the centripetal force is equal to the gravitational force (mg), as the normal force is zero. Therefore, the correct answer to the problem is option (a) mg.

PREREQUISITES
  • Understanding of centripetal force and its formula, Fc = (MV^2)/R
  • Basic principles of forces acting on objects in motion
  • Knowledge of gravitational force and its impact on objects
  • Familiarity with roller coaster dynamics and minimum speed calculations
NEXT STEPS
  • Study the derivation of centripetal force equations in circular motion
  • Learn about the role of normal force in vertical loops of roller coasters
  • Explore the concept of minimum speed required for circular motion
  • Investigate real-world applications of centripetal force in amusement park rides
USEFUL FOR

This discussion is beneficial for physics students, engineering students, and anyone interested in the mechanics of roller coasters and circular motion dynamics.

XwakeriderX
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Homework Statement


A roller coaster goes through an inside vertical loop at the minimum speed required to just barely make it through the top of the vertical track. At the very top of the track, the magnitude of the centripetal force acting on the 'coaster is
a. mg.
b. 2 mg.
c. 6 mg.
d. 1/2 mg.
e. 5/2 mg





Homework Equations


Fc=(MV^2)/2



The Attempt at a Solution


My guess is there is only a normal force acting on it so its MG?
 
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Hi XwakeriderX! :smile:
XwakeriderX said:
A roller coaster goes through an inside vertical loop at the minimum speed required to just barely make it through the top of the vertical track. At the very top of the track, the magnitude of the centripetal force acting on the 'coaster is
a. mg.
b. 2 mg.
c. 6 mg.
d. 1/2 mg.
e. 5/2 mg

My guess is there is only a normal force acting on it so its MG?

I would have said that the centripetal force was zero

there are generally only two forces on the coaster, its weight (which isn't generally centripetal) and the normal reaction force (which is always centripetal),

but "at the minimum speed required", the normal force at the top must be zero :confused:

(maybe they mean the mass times the centripetal acceleration??)
 
Hmm well it has to be one of those...it just doesn't make sense because at the top the centripetal should equal mg meaning its zero? or is there no centripetal so its just mass and gravity acting on it?
 

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