Magnitude of Electric Field in Cell Membrane?

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Homework Help Overview

The problem involves calculating the magnitude of the electric field across a cell membrane given a potential difference and the thickness of the membrane. The subject area relates to electrostatics and electric fields.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the formula E = V/r to find the electric field but questions the validity of their calculation. Participants discuss the implications of dividing by a small number and the expected magnitude of the result.

Discussion Status

Participants are engaged in checking the calculations and discussing potential errors in the original poster's approach. There is a suggestion to reconsider the exponent in the calculation, indicating an ongoing exploration of the problem.

Contextual Notes

The original poster's answer was flagged as incorrect, prompting further examination of the calculations and assumptions involved in the problem.

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[SOLVED] magnitude of electric field.

Homework Statement



The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a potential difference of about 0.060 V exists across the membrane.

The thickness of the membrane is 9.00 x 10^-9 m. What is the magnitude of the electric field in the membrane?
in V/m


i believe the equation to be: E = V/r

not sure why .060 / 9.00 x 10^-9 would not work?

Homework Equations





The Attempt at a Solution





it says my answer of: 6.7E-6 is incorrect??
 
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You are dividing a number by a VERY small number. This means that your answer should be a very big number. 6.7E-6 is not very big. Check your math. I think you may have made an sign error with your exponent.
 
Okay thanks, 6.7E6
 
Anytime.:smile:
 

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