Magnitude of Friction Force - Circular Motion

[Chica1975]

Homework Statement

A car of mass 1164kg was traveling around a 288m radius corner at a speed of 10.8m/s. What was the magnitude of the fiction force required to maintain the vehicles path?

Homework Equations

F=ma
I have no idea after that

The Attempt at a Solution

I found mg = 11407.20

Can someone please explain about frictional force, I find this very hard, I have read and reread a lot of info but I just don't get it. Especially when I have to apply it to problems and I don't have the coefficient.

I am really stuck, please help!

 

[willem2]

You don't need to know anything about friction to solve this. You just need to know the acceleration of the car, which is in circular motion with constant speed.
The only force that can cause this acceleration is the friction force.

 

[Chica1975]

Thanks but I still have no idea how to tackle this. Can someone please help me.

 

[Chica1975]

Anyone?

 

[rwisz]

The magnitude of the friction force in this scenario can be found by using the equation F=ma, where F is the friction force, m is the mass of the car, and a is the centripetal acceleration.

To find the centripetal acceleration, we can use the equation a=v^2/r, where v is the velocity and r is the radius of the circular path. In this case, the velocity is given as 10.8m/s and the radius is 288m. Plugging in these values, we get a=10.8^2/288 = 0.406 m/s^2.

Now, we can plug this value of a into the first equation to find the friction force. F = (1164kg)(0.406m/s^2) = 472.184 N.

The friction force in this case is acting inwards towards the center of the circular path, and it is necessary to maintain the car's path along the curved road. Without this force, the car would continue in a straight line and not be able to make the turn.

The coefficient of friction is not needed in this calculation as it is dependent on the type of surface the car is traveling on. However, it is important to consider the coefficient of friction in real-life situations as it can have a significant impact on the magnitude of the friction force.