Magnitude of Potential Difference Between Two Points

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The discussion revolves around calculating the potential difference between two points, A and B, with a current of 1.2 A. The key formula used is Δv = IR, where R is the equivalent resistance. Participants emphasize the need to correctly add resistors in series and parallel to find R_eq. After clarifying the process, one participant successfully calculates R_eq as 5Ω, leading to a potential difference of 6 V. The conversation highlights the importance of understanding resistor combinations in circuit analysis.
anomalocaris
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potential diffeence.jpg
1. Homework Statement [/b]

So I found this problem online, and I really do not know how to go about solving it! My professor has done similar problems in class, but it's still a little confusing.

A current of 1.2 A flows from A to B. Therefore, the magnitude of the potential difference between points A and B is approximately

Homework Equations


I know Δv=IR and Ampere/Volt makes an Ω

The Attempt at a Solution



Well, the image attached already gives the answer, it should be 6.0 V. The current is given (1.2 A), so I'm guessing by the units that I must multiply something with Ω to get Volts. Should I add up the resistors?

Thank you!
 
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To do this problem, you are going to need to be able to "add" resistors in parallel and series. Need help with that?
 
anomalocaris said:
Well, the image attached already gives the answer, it should be 6.0 V. The current is given (1.2 A), so I'm guessing by the units that I must multiply something with Ω to get Volts. Should I add up the resistors?

Sure. Find the equivalent resistance between points A and B. Then see what potential drop occurs across it due to the given current value.
 
lewando said:
To do this problem, you are going to need to be able to "add" resistors in parallel and series. Need help with that?


Haha, lewando, yes please!

Would we consider the two 6Ω resistors parallel? And if so, the potential difference there is the same? We are getting to the point where I just smile and nod during the lecture even though I am completely lost!
 
lewando said:
Well then take a look at the following two websites:
http://www.allaboutcircuits.com/vol_1/chpt_5/1.html (for a definition of series/parallel)
http://en.wikipedia.org/wiki/Series_and_parallel_circuits (for how to combine them)

Give them a read and come back with any questions.

Thank you so much! I just had an epiphany and this is all way less complicated! Thank you to all who replied. And thank you so much, lewando. I wasn't taking the reciprocals of the resistances and so I was adding them incorrectly, but now it all makes much more sense. I ended up with an R_eq of 5Ω, which when multiplied by 1.2 A yields a potential difference of 6 V. Thank you so much!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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