Magnitude of tension force using moment

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SUMMARY

The discussion focuses on calculating the tension force in three cables lifting a uniform steel ring with a diameter of 60 inches and a weight of 600 lbs. The cables are each 50 inches long and attached at angles of 90 degrees for points A and B, and 120 degrees for point C. Initial estimates suggested a force of 250 lbs for the first two cables and 100 lbs for the third, but these were incorrect due to the need for a more precise calculation involving moment equations and the specific geometry of the setup.

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kleeds
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Homework Statement


a uniform steel ring 60" in diameter and weighing 600 lbs is lifted by three cables each 50" long attached at points A (90*) B (90*) C (120*) with a radius of 30". compute the magnitude of tension force in each cable

Homework Equations


all moment equations
ft=ma

The Attempt at a Solution


first two cables have a force of 250 lbs and last one has 100 lbs. more of an incorrect guess figured since two have the same angle they would be the same. since there is almost no acceleration (besides gravity) i don't think i could solve it with my equation. it also wouldn't help because i need tension in each string not one tension.

note: degrees=*
 
Last edited:
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welcome to pf!

hi kleeds! welcome to pf! :smile:

kleeds said:
a uniform steel ring 60" in diameter and weighing 600 lbs is lifted by three cables each 50" long attached at points A (90*) B (90*) C (120*) with a radius of 30". compute the magnitude of tension force in each cable

i don't understand what the tops or bottoms of the cables are attached to, or what those angles are :confused:
 

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