The Attempt at a Solution
1) Find I and voltage across resistor 5
12.6 = I * 5.08
12.6-.1984= 12.4 V across battery.
So would I and V across the resistor be I=2.48 and V=12.4?
2) Find current I
(Forgot to mark, I is going clockwise)
Total resistance is 20. Would I simply add the two batteries making V=20?
V=IR 20=I20 I=1?
3) Find current through each resistor. Give magnitude and direction of current flow.
Kind of lost on this one. I have a feeling I need to do kirchoffs rule. How would I handle the battery in the center? I only have examples with the center having a resistor to go off from. The flow was also specified for me. How would I determine the flow if I am not given that information? :(
So far I took the loop counter clockwise from positive end for the top part and current heading towards the right in the center.
12V-3I(1) -6I(2) + 3V= 15V -3I(1)-6I(2) = 0
Bottom counter clockwise from negative end.
-6V-2I(3) +6I(2) -3V = 0
-9V - 2I(3)+6I(2)=0
Look anywhere right so far?