1. Two planes are each about to drop an empty tank. At the moment of the release each plane has the same speed of 135 m/s, and each tak is at the same height of 2.00 km above the ground. Although the speeds are the same, the velocities are different at the instant of release, because one plane is flying at an angle of 15.0 degrees above the horizontal, and the other is flying at an angle of 15.0 degrees below the horizontal. Find the magnitude and direction of the velocity with which the fuel tank hits the ground if it is from plane A(15 degrees above the horizontal), and plane B(15 degrees below horizontal). In each part, give the directional angles with respect to the horizontal.(adsbygoogle = window.adsbygoogle || []).push({});

2. Relevant equations: X= Xo+Vot+1/2 at^2 (same for y)

Vx= Vo+at (same for y)

I found my time to be 408 seconds (2 Xdistance in m(2000m)/a(9.8 m/s)

I then added my x and y coodinates for plane A:X=130, Y=35; for plane B: X=-130, y=-35. For the most pary im lost. I'm not sure of how to find my y velocity or if I need to find it. Please help!

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Magnitue and direction of velocity

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