Man pulling himself up at 0.2m/s^2

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Homework Help Overview

The problem involves a man with a mass of 70 kg sitting on a chair weighing 10 kg, who is attempting to pull himself upwards with an acceleration of 0.2 m/s². The objective is to determine the force required to achieve this acceleration, considering the effects of gravity.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the total mass involved in the problem, with some suggesting that only the man's mass should be considered, while others clarify that both the man and the chair are being pulled upwards. There are attempts to apply the equation F=ma, but confusion arises regarding the correct interpretation of forces and acceleration.

Discussion Status

The discussion is ongoing, with participants providing insights and corrections regarding the setup of the problem. There is recognition of the complexity introduced by the pulley system, and some guidance is offered about drawing a free body diagram to better understand the forces at play.

Contextual Notes

Participants are navigating assumptions about the system, including the role of gravity and the configuration of the pulley system. There is mention of potential issues with significant figures and arithmetic in the calculations presented.

thedarkone80
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Homework Statement


A man with an 70kg mass, sits on chair of 10kg, and pulls himself upwards at a acceleration of 0.2m/s^2. What is the force needed to achieve this acceleration?


Homework Equations



F=ma

The Attempt at a Solution


F=(80)*(9.81+0.2)
F=(80)*(9.81-0.2)
Neither are giving a correct answer, please help!
 
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Well, he's not going to take the chair with him when he pulls himself up, I take it? So the mass is 70kg only.

Remember that the force of gravity is acting in the opposite direction to the direction the man is accelerating in. Taking the direction of acceleration due to gravity to be positive, and the direction of acceleration of the man to be negative (since it is against gravity) then the overall acceleration is 9.81 + (-0.2) = 9.61.
 
no, he is pulling himself and the chair upwards, he is on a pully system. sorry for not being clear. appreciate the quick response though!
 
thedarkone80 said:

Homework Statement


A man with an 70kg mass, sits on chair of 10kg, and pulls himself upwards at a acceleration of 0.2m/s^2. What is the force needed to achieve this acceleration?


Homework Equations



F=ma

The Attempt at a Solution


F=(80)*(9.81+0.2)
F=(80)*(9.81-0.2)
Neither are giving a correct answer, please help!
One of these last 2 equations is correct (do you know which?) There might be a problem with the number of significant figures you gave in your answer, or you could have done the arithmetic wrong. Since you didn't say what answer you got, it's hard to tell.
 
thedarkone80 said:
no, he is pulling himself and the chair upwards, he is on a pully system. sorry for not being clear. appreciate the quick response though!

Just read this more carefully, I didn't realize before there is a pulley system involved.

Have you drawn a free body diagram for the man+chair? In how many different places is a rope attached to them, including where the man is holding the rope to pull himself up?
 

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