Map of Area Bounded by y=5x & y=-3x in Upper Plane

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The discussion focuses on the mapping of the area bounded by the lines y=5x and y=-3x in the upper half-plane under the transformation w=1/z. The lines in the z-plane are represented as z(t) = t + 5ti and z(t) = t - 3ti, leading to the corresponding mappings w1 and w2. The resulting lines in the uv-plane are v = -5u and v = 3u. The point (0,1) is confirmed to be within the bounded area, indicating that its image under the mapping should also be included in the w-plane.

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Amer
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what is the map of the area bound by y=5x and y=-3x in the upper half plane, under w=1/z we have the lines : $ z(t) = t + 5t i $ , and the line $z(t) = t - 3ti $
Fist line
$\displaystyle w_1 = \dfrac{1}{t+5ti} = \dfrac{1}{26t} - \dfrac{5i}{26t} $
Second
$\displaystyle w_2 = \dfrac{1}{t - 3ti} = \dfrac{1}{10t} + \dfrac{3i}{10t} $

We get the lines in the uv plane

$v = -5u \; , v=3u $
taking a point in the area for example (0,1) under 1/z (0,1) so we will take the bounded area between $v = -5u \; , v=3u $ which has the point (0,1)
is that right ?
Thanks
 
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You have correctly found the boundary lines as $v = -5u$ and $v=3u $. But if the original area in the $z$-plane contains the point $(0,1)$ then the image in the $w$-plane should contain the image of that point under the map $w=1/z$.
 

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