Mapping a complex circle to its square

[torquerotates]

Homework Statement

graph |z-1|=1 and then graph z^2

Homework Equations

z=x+iy

The Attempt at a Solution

well, |z-1|=1 => |(x-1)+iy|=1,

squaring both sides. we get, (x-1)^2+y^2=1. This is a circle. But how am i supposed to get z^2 from this? I don't know what to do with the inequality since i can't algebrically isolate the z.

 

[Mark44]

I'm confused, too. Maybe you're supposed to take the z values on the circle and square them. If that's the case, what you'd be graphing is the set {(z, z^2): |z - 1| = 1}.

If I were you, I'd get clarification from my prof.