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Mapping a complex circle to its square

  1. Jan 20, 2009 #1
    1. The problem statement, all variables and given/known data
    graph |z-1|=1 and then graph z^2



    2. Relevant equations
    z=x+iy



    3. The attempt at a solution

    well, |z-1|=1 => |(x-1)+iy|=1,

    squaring both sides. we get, (x-1)^2+y^2=1. This is a circle. But how am i supposed to get z^2 from this? I dont know what to do with the inequality since i cant algebrically isolate the z.
     
  2. jcsd
  3. Jan 21, 2009 #2

    Mark44

    Staff: Mentor

    I'm confused, too. Maybe you're supposed to take the z values on the circle and square them. If that's the case, what you'd be graphing is the set {(z, z^2): |z - 1| = 1}.

    If I were you, I'd get clarification from my prof.
     
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