Marginal Density of Coordinates Inside an Ellipse

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SUMMARY

The discussion focuses on finding the marginal densities of the X and Y coordinates for a point chosen randomly within an ellipse defined by the equation (x/a)^2 + (y/b)^2 = 1. The density function for the coordinates is established as f_{x,y} = 1/∏ab, where ∏ab represents the area of the ellipse. The limits of integration for calculating the marginal density of X are confirmed to be -(b/a)√(a² - x²) and (b/a)√(a² - x²), which accurately define the range of Y values for any given X.

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Homework Statement



A point is chosen randomly in the interior of an ellipse:

(x/a)^2 + (y/b)^2 = 1

Find the marginal densities of the X and Y coordinates of the points.

Homework Equations



NA

The Attempt at a Solution



So this ought to be uniformly distributed, thus the density function for (x,y) is f_{x,y} = 1/∏ab (where ∏ab is the area of the ellipse)

So, to find the marginal density for x (and later for y), I realize that I just need to find the limits of integration and then go about my business. I believe that the limits of integration are
-(b/a)\sqrt{a^2 - x^2} and b/a\sqrt{a^2 - x^2},

since these should be the minimum and maximum values that y can take for any given x. Are these limits of integration and/or is my reasoning correct?

As always, many thanks to all of you wonderful Homework Helpers!
 
Last edited:
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That seems entirely correct.
 
clamtrox said:
That seems entirely correct.

Excellent, thanks!
 

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